Ch 9 Proof

<body topmargin=0 leftmargin=0 marginheight=0 marginwidth=0> <table cellpadding=0 cellspacing=0 border=0><tr> <td valign="top" height=90 BGCOLOR="#006699" TEXT="#080000" bgproperties="fixed" background="02c285a1erlcgo.png"> <div> <FONT SIZE="5" COLOR="#FFCC66" FACE="Arial" ><B>The Geocentric Bible </B></FONT><B>    </B><B> |     </B><A HREF="index.htm" TARGET="_top" TITLE="The Geocentric Bible "><U><B>home</B></U></A></div> <div> <A HREF="id17.htm" TARGET="_top" TITLE="Preface"><U>Preface</U></A>   |   <A HREF="id18.htm" TARGET="_top" TITLE="Ch1Scripture"><U>Ch1-Scripture</U></A>   |   <A HREF="id19.htm" TARGET="_top" TITLE="Ch 2 Evidence"><U>Ch 2 Evidence</U></A>   |   <A HREF="id21.htm" TARGET="_top" TITLE="Ch 3 First Second of Creation"><U>Ch 3 First Second of Creation</U></A>   |   <A HREF="id22.htm" TARGET="_top" TITLE="Ch 4 The Revolving Heaven"><U>Ch 4 The Revolving Heaven</U></A>   |   <A HREF="id23.htm" TARGET="_top" TITLE="Ch 5 Density Center of Universe"><U>Ch 5 Density & Center of Universe</U></A>   |   <A HREF="id24.htm" TARGET="_top" TITLE="Ch 6 Preserving"><U>Ch 6 Preserving</U></A>   |   <A HREF="id25.htm" TARGET="_top" TITLE="Ch 7 A Relatively Small Universe"><U>Ch 7 A Relatively Small Universe</U></A>   |   <A HREF="id29.htm" TARGET="_top" TITLE="Ch 8 Lesser"><U>Ch 8 Lesser</U></A>   |   <B>Ch 9 Proof</B>   |   <A HREF="id26.htm" TARGET="_top" TITLE="Ch 10 Links Contact Us"><U>Ch 10 Links - Contact Us</U></A></div> <div> </div> </td> </tr><tr> <td valign="top" height=390 BGCOLOR="#FFFFFF" TEXT="#080000"> <div> <I>Ch 9 Proof</I></div> <div> Enclosed is proof of geocentricity. </div> <bR> <div> Gerardus Bouw has a Ph.D. in astronomy.</div> <div> David Thompson is a commercial (Delta) airplane pilot:</div> <bR> <div> About 25 of us who accept in geocentricity met in Houston recently. One of the speakers, who lives in Houston, said that he had visited earlier with an official from the National Acronautical Space Administration about launching rockets into space. He said, “Don't they actually figure launches from a stationary earth and not the earth revolving daily on its axis?” The official said only that it is more “convenient.” He should have said that if we figure the launching a rocket from a spinning earth, the rocket would not hit the target. The truth is that whether they figure the earth revolving daily or figure from a stationary earth, the mathematics come out the same. However, figuring rocket launches from a revolving earth is a mathematical nightmare. If NASA would admit the truth, then Bible would no longer be overruled by science.</div> <bR> <div> In the following diagram, the one plane going north-south and the other going east-west shows that there is a difference in travel times. The Michelson-Morley experiment does the same thing by measuring the earth's travel in a straight line in it's annual orbit around the sun. However, no straight line movement of the earth was found. The secular explanation is that the Michelson-Morley experiment was not accurate enough. However, the truth is that the earth really is not moving. If it was moving, the movement would have been detected. This means that neither is the earth spinning on its axis daily, it is stationary in the center of the universe.</div> <bR> <div> Gerardus Bouw has a Ph.D. in astronomy.</div> <div> let's say that the wind is blowing from left to right at 20 feet per</div> <div> second and that our plane flies 100 feet per second. That means that the</div> <div> plane has to fly the equivalent of the hypotenuse of a triangle whose</div> <div> base (l-r) is 20 feet per sec and whose hypotenuse is 100 ft/sec. Using</div> <div> the Pythagorean Theorem, the speed at which the plane flies north and</div> <div> south is 98 ft/sec.</div> <bR> <div> Let's say that we send one plane across the wind (N-S) for 1000 feet and</div> <div> another plane E-W for 1000 feet. The north-south plane will take 1000 ft</div> <div> divided by 98 ft/sec = 10.2 seconds to go north and 10.2 seconds to fly</div> <div> south for a round trip time of 20.4 seconds.</div> <bR> <div> The E-W plane flies the first 1000 feet at 100+20 = 120 feet per second</div> <div> and traverses the distance in 1000/120 = 8.3 seconds. On the return leg</div> <div> it moves at 80 ft/sec (100-20).  It thus takes 1000/80 = 12.5 seconds. So</div> <div> the horizontal round trip time is 8.3+12.5 = 20.8 seconds.</div> <bR> <div> We see that it takes 0.4 seconds longer to do the horizontal round trip</div> <div> (20.8 sec) than it does to take the vertical round trip (20.4 sec). That</div> <div> is the time difference that Michelson and Morely were looking for and did</div> <div> not find.</div> <bR> <div> <IMG SRC="0f230a00.jpg" border=0 width="1072" height="1696" ALIGN="BOTTOM" HSPACE="0" VSPACE="0"></div> <bR> <div> <IMG SRC="0f330a00.jpg" border=0 width="1072" height="1696" ALIGN="BOTTOM" HSPACE="0" VSPACE="0"></div> <bR> <div> From a commercial (Delta) airplane pilot:</div> <div> The wind speed is 50 mph.</div> <div> The airplanes speed is 100 mph.</div> <div> Distance to travel 400 miles out and 400 miles back to the starting point in a straight line.</div> <bR> <div> Note: airplanes in flight have no relationship to the ground, only airspeed. Navigation is used to keep the airplane on course relative to the ground. In other words, when a plane is flying just above a solid cloud layer the pilot without navigational instruments does not know which way the wind (and therefore clouds) are moving. To him the clouds seem stationary whether they are or not. If a pilot was making circles in the air on a windless day he would pass over the same clouds again and again. Similarly if he was making circles on a windy day he would pass over the same clouds again and again. There is no difference as far as the pilot is concerned. However, an observed standing on the ground listening up through would hear the plane go round and round on a windless day, but drift downwind along with the clouds on a windy day.</div> <bR> <div> So, the plane on the north south track would have to turn into the wind to compensate for drifting downwind. In our case the high winds would require the pilot to turn 45 degrees into the wind. His airspeed would still be 100 mph, but like the sides on a 30 degree triangle his ground speed would be less. From trigonometry we can calculate that his ground speed would be .866 on the his airspeed or 86.6 mph. He would have the same ground speed while heading north as well as south. So to travel the 400 miles north at a ground speed of 77.5 miles would take</div> <div> 400 miles headed north divided by 86.6 miles per hour= 4.62 hours</div> <div> 400 miles headed south divided by 86.6 miles per hour= 4.62 hours</div> <div>                                Total round trip   flying hours                   9. 24                                  </div> <div> Or just under 9 ½ hours to complete the journey. Don't get lost in the trigonometry numbers…just be patient.</div> <bR> <div> Now consider the plane flying East then West. As he flew east he would have a tailwind of 50 mph. His airspeed is still 100 mph. He would make it out and back to the far point of 400 miles in:</div> <div> 400 miles headed north divided by 150 miles per hour= 2.67 hours</div> <div> 400 miles headed south divided by 50 miles per hour=  8.00 hours</div> <div>                     Round trip flying hours                 Total           10.67  </div> <bR> <div> However, when he turned around into the wind to head home he would still have airspeed of 100 mph. BUT, the ground speed would be ZERO! He would never make it back to home base! Even if he refueled several times he could make no progress back towards home.</div> <bR> </td> </tr></table></body>